ANSWERS: 1
-
AB is in the plane. So is BC so b-a and c-b are in the plane. So (b-a) x (c-b) is normal to the plane. = bxc - axc -bxb + axb = bxc - axc + axb (bxb is zero) = axb + bxc - axc = axb + bxc + cxa It almost does itself.
Copyright 2023, Wired Ivy, LLC