A ball is thrown vertically upwards with an initial speed of 20 m/s. What is the time taken for the ball to eturn to the thrower and what is the maximun speed reached?
by 
Ary180
ANSWERS: 1
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First you need the height. Since it's straight up it is easy h= v^2/2g..otherwise...v^2sin(90)^2/2g 20^2/2g=400/19.614=20.39 meters now time...t=SQRT(2d/gsin@) for this it is SQRT(2D/g)=SqRT(40.8/9.807)=2.04 seconds.. this is just to reach the height.. so double for total time...4.08 secs From release on the way up the acceleration is negative so unless the way down allows for a velocity above 20 mps... v=vo+at since the velocity as the ball starts to descend is zero...v=at = v=gt = 9.807*2.04=20.0031 mps so the velocity barely exceeds its initial or ultimately the anser is 20 mps
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