A skateboarder, starting from rest, rolls down a 15m ramp. When she arrives at the bottom of the ramp her speed is 6.80 m/s. What is her acceleration, if the aceleration is constant?
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jonnyu33
ANSWERS: 1
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The velocity and the distance are related by the equation v^2 = u^2 +2as where v is the final velocity, u is the initial velocity, the constant acceleration and s the covered. Given u = 0, v = 6.8 m/s, a =? s = 15 m Thus, (6.8)^2 = 0 +2*a*15 This gives a = 6.8*6.8/30 = 1.54 m/s^2
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